Good afternoon Fred,
It will depend on the relay specification. Digital outputs 1 to 8 can sink up to 50 VDC 100 mA but we need to know the requirements of your relay?
dataTaker does not supply the power for your relay, it is simply the switch that turns the power on or off. You will need to have a power supply that matches the requirements of the relay and does not exceed the capability of the DT800.
Your relay will need to operate less that 50 VDC (12 VDC would be good) and a current draw of less than 100 mA or you will damage the dataTaker. If the relay exceeds these figures the use a smaller relay to switch the bigger relay.
The positive of the power supply will connect to the coil of the relay. Then connect the other side to the digital channel on the DT800. To complete the circuit connect the digital ground to the DT800 to the ground side of the power supply.
If your relay is normal open to close the contact you need to set the digital output to 0. (This turns on the power)
Cheers,
Roger
Good afternoon Fred,
It will depend on the relay specification. Digital outputs 1 to 8 can sink up to 50 VDC 100 mA but we need to know the requirements of your relay?
dataTaker does not supply the power for your relay, it is simply the switch that turns the power on or off. You will need to have a power supply that matches the requirements of the relay and does not exceed the capability of the DT800.
Your relay will need to operate less that 50 VDC (12 VDC would be good) and a current draw of less than 100 mA or you will damage the dataTaker. If the relay exceeds these figures the use a smaller relay to switch the bigger relay.
The positive of the power supply will connect to the coil of the relay. Then connect the other side to the digital channel on the DT800. To complete the circuit connect the digital ground to the DT800 to the ground side of the power supply.
If your relay is normal open to close the contact you need to set the digital output to 0. (This turns on the power)
Cheers,
Roger