Hi,
I hope you can help, I am new and overwhelmed! I have a Maxbotix 7060 ultrasonic sensor that I need to help me measure distance of an object.
The sensor requires a 3 to 5 volt dc source and returns a voltage as a ratio of the voltage in: (Vcc/1024) per cm - so 5V yields ~4.9 mV/cm. I am using an external (fairly stable) 5 Vdc power source and currently have the sensor returning data using 1V("Ultrasonic",.2) (.2 factor to divide by 5 millivolts) and I know that this is not really the correct way to do it.
My question is should I be using the DT800 for excitation instead of my external power source so that I can monitor the supply power and calculate more accurately? And if so how do i program that - also how would I connect it? My sensor has 3 terminals (of importance) ground, +5 Vdc, and analogue. Its is the analogue that returns the ratio of input Vcc by cm.
I would also really like to watch all of the videos on programming and using the DT800 but the links are all dead, do you have them available anywhere?
Cheers,
Ben
Hi,
I hope you can help, I am new and overwhelmed! I have a Maxbotix 7060 ultrasonic sensor that I need to help me measure distance of an object.
The sensor requires a 3 to 5 volt dc source and returns a voltage as a ratio of the voltage in: (Vcc/1024) per cm - so 5V yields ~4.9 mV/cm. I am using an external (fairly stable) 5 Vdc power source and currently have the sensor returning data using 1V("Ultrasonic",.2) (.2 factor to divide by 5 millivolts) and I know that this is not really the correct way to do it.
My question is should I be using the DT800 for excitation instead of my external power source so that I can monitor the supply power and calculate more accurately? And if so how do i program that - also how would I connect it? My sensor has 3 terminals (of importance) ground, +5 Vdc, and analogue. Its is the analogue that returns the ratio of input Vcc by cm.
I would also really like to watch all of the videos on programming and using the DT800 but the links are all dead, do you have them available anywhere?
Cheers,
Ben