Good morning Grant,
I am going to make some assumptions here just to get us started.
At this stage we are just trying to get a resistance reading from the sensor, then we can try a reading a few resistances at different temperatures and refine the calculations.
IF the Thermistor is from MEAS then it might be a 44108 http://www.meas-spec.com/downloads/44108.pdf
Looking at the data sheet we see the resistance at 0 deg C is 94,980 Ohms. This is much greater than the maximum 10,000 Ohms the DT80 can read so we need to use a parallel resistor
The calculation for a parallel resistor is on page 295 of the DT80 manual (UM-0085-B7)
Rp = (10000 x 94980)/(94980 - 10000) = 11,176 Ohms
So that would be a 12 KOhm resistor of 0.0% or better.
Wire this up as per Figure R6 on page 294 and use the calculation shown to return the resistance value of the Thermistor.
When we can read resistances we can then look at a more exact temperature resistance curve and calculate the Steinhart-Hart coefficients
Cheers,
Roger
Good morning Grant,
I am going to make some assumptions here just to get us started.
At this stage we are just trying to get a resistance reading from the sensor, then we can try a reading a few resistances at different temperatures and refine the calculations.
IF the Thermistor is from MEAS then it might be a 44108 http://www.meas-spec.com/downloads/44108.pdf
Looking at the data sheet we see the resistance at 0 deg C is 94,980 Ohms. This is much greater than the maximum 10,000 Ohms the DT80 can read so we need to use a parallel resistor
The calculation for a parallel resistor is on page 295 of the DT80 manual (UM-0085-B7)
Rp = (10000 x 94980)/(94980 - 10000) = 11,176 Ohms
So that would be a 12 KOhm resistor of 0.0% or better.
Wire this up as per Figure R6 on page 294 and use the calculation shown to return the resistance value of the Thermistor.
When we can read resistances we can then look at a more exact temperature resistance curve and calculate the Steinhart-Hart coefficients
Cheers,
Roger